Thursday, January 31, 2013

Solving Online Calculus Optimizing Problems


Study of rate of transformation is called calculus. Study of optimization calculus or mathematical encoding is disturbed to influence the excellent element from the group of elements. Optimization is a single technique to obtain a maximum or minimum value of a function. The smaller value of the function is known as minimum. The greater value of the function is known as maximum.

Online has emerged as one of the main key source for students to increase their knowledge topic wise.

Examples to Solving Online Calculus for Optimizing Problems:

Solving online calculus for optimizing example problems 1:

`y = 3x^2 - 5x` , solving for x and y for the optimizing calculus problems.

Solution:

Step 1: Equation is` y = 3x^2- 5x`

Step 2: Differentiate with respect to x

`dy / dx` = 6x - 5

Equate `dy / dx ` to 0.

`dy / d` x = 6x - 5 = 0

6x = 5

x = `(5) / 6` or   0.83

Step 3: Plug x = 0.83 in the given equation

y = `3 (0.83) ^2- 5(0.83)`

= 3(0.6889) - (4.15)

= 2.06 - 4.15

= -2.09

Therefore, x = 0.83 and y = -2.09

Step 4: From the given equation plot the graph and mark out the points in the graph.

Graph to study optimizing problem



Solving Online Calculus for Optimizing Example Problems 2:

`y = 5x^2 - 19x,` solving for x and y for the optimizing calculus problems.

Solution:

Step 1: Equation is `y = 5x^2- 19x`

Step 2: Differentiate with respect to x

`dy / dx ` = 5x - 19

Equate `dy / dx` to 0.

` dy / dx` = 10x - 19 = 0

10x = 19

x = `(19)/10`  or 1.9

Step 3: Plug x = 1.9 in the equation

y = `5(1.9) ^2- 19(1.9)`

= 5(3.61) - 36.1

= 18.05 - 18.05

= -18.05

Therefore, x = 1.9 and y = -18.05

Step 4: From the given equation plot the graph and mark out the points in the graph.

Graph to study optimizing problem

I like to share this calculus problems with you all through my article.

Solving Online Calculus for Optimizing Example Problems 3:

`y = 4x^2- 7` , solving for x and y for the optimizing calculus problems.

Solution:


Step 1: The given equation is `y = 4x^2- 7`

Step 2: Differentiate with respect to x

`dy / dx ` = 8x

Step 3: Equate `dy / dx` = 0

8x = 0

x = 0

Step 4: Thus, `y = 4(0) ^2-7`

y = -7

So, x = 0 and y = -7.

Step 4: From the given equation plot the graph and mark out the points in the graph.

Graph to study optimizing problem

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