In this section we will see about trigonometry xi. Eleventh average trigonometry is also recognized as the division of the main dealing with trigonometry functions, angle, etc. It gives the association and angles in detail with their problems. Sine, Cosine and Tangent are the trigonometric meaning concerned in trigonometric semi position identity. We have worked problems and practice problems along with solution in below. Let us see about the topic trigonometry xi.
Solved Problems for Trigonometry Xi:
Let us see about the topic trigonometry xi,
Having problem with Sine and Cosine Read my upcoming post, i will try to help you.
Solved problem 1: Try to calculate the radius of the circle in which a central angle of 45 degree intercepts an arc of length 10 cm. (use π value as `22/7` )
Solution:
Given length = 10 cm and angle = 45 degree
θ = 45 degree = `(45Pi) / 180` = π/4
r = l/ θ
r = `(10 * 4) /Pi` = `(10 * 4 *7) / 22` = 12.72 cm
Therefore, the radius of the circle = 12.72 cm.
Answer: The radius of the circle = 12.72 cm.
Solved problem 2: If cos x = `1/5` , x lies in the first quadrant. Carry out step of the values of other five trigonometric functions.
Solution:
Given cos x = `1/5` , therefore, sec x = 5
We know that,
sin2 x + cos2 x = 1, that is sin2 x = 1 – cos2 x
sin2 x = 1 - `1/5` =`4/5`
sin x = ± `2/(sqrt 5)` (take square root on both sides)
x lies in 1st quadrant, sin x is negative.
Therefore, sin x = `2/(sqrt 5)` which also gives
cosec x = `2/(sqrt 5)`
Further, we have tan x = `(sin x)/(cos x)` = `(5(sqrt 5))/2` and cot x = `(cos x) /(sin x)` = `(2)/(5(sqrt 5))`
Answer: sec x = 5, sin x = `2/(sqrt 5),` cosec x = `2/(sqrt 5)` , tan x = `(5(sqrt 5))/2` , cot x =`2/(5(sqrt 5))`
Practice Problems for Trigonometry Xi:
Let us see about the topic trigonometry xi,
Practice problem 1: Determine the value of cos (370°).
Practice problem 2: Find the value of sin 5pi/3.
Solutions for prepare for trigonometry xi:
Solution 1: The value of cos (370°) is 0.98.
Solution 2: The value of sin 5pi/3 is -0.87.
I like to share this syllabus for iseet exam 2013 with you all through my article.
Solved Problems for Trigonometry Xi:
Let us see about the topic trigonometry xi,
Having problem with Sine and Cosine Read my upcoming post, i will try to help you.
Solved problem 1: Try to calculate the radius of the circle in which a central angle of 45 degree intercepts an arc of length 10 cm. (use π value as `22/7` )
Solution:
Given length = 10 cm and angle = 45 degree
θ = 45 degree = `(45Pi) / 180` = π/4
r = l/ θ
r = `(10 * 4) /Pi` = `(10 * 4 *7) / 22` = 12.72 cm
Therefore, the radius of the circle = 12.72 cm.
Answer: The radius of the circle = 12.72 cm.
Solved problem 2: If cos x = `1/5` , x lies in the first quadrant. Carry out step of the values of other five trigonometric functions.
Solution:
Given cos x = `1/5` , therefore, sec x = 5
We know that,
sin2 x + cos2 x = 1, that is sin2 x = 1 – cos2 x
sin2 x = 1 - `1/5` =`4/5`
sin x = ± `2/(sqrt 5)` (take square root on both sides)
x lies in 1st quadrant, sin x is negative.
Therefore, sin x = `2/(sqrt 5)` which also gives
cosec x = `2/(sqrt 5)`
Further, we have tan x = `(sin x)/(cos x)` = `(5(sqrt 5))/2` and cot x = `(cos x) /(sin x)` = `(2)/(5(sqrt 5))`
Answer: sec x = 5, sin x = `2/(sqrt 5),` cosec x = `2/(sqrt 5)` , tan x = `(5(sqrt 5))/2` , cot x =`2/(5(sqrt 5))`
Practice Problems for Trigonometry Xi:
Let us see about the topic trigonometry xi,
Practice problem 1: Determine the value of cos (370°).
Practice problem 2: Find the value of sin 5pi/3.
Solutions for prepare for trigonometry xi:
Solution 1: The value of cos (370°) is 0.98.
Solution 2: The value of sin 5pi/3 is -0.87.
I like to share this syllabus for iseet exam 2013 with you all through my article.
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