Solving 2nd order derivatives of a function
1) Solve the derivative for the function f(x) = x^2 + 8x + 9
Solution : The given function is f(x) = x^2 + 8x + 9
Differentiate the above equation with respect to 'x' . It is represented as f'(x) .
f'(x) = `(d(x^2))/dx` + `(d(8x))/dx` + `(d(9))/dx` .
f'(x) = 2x + 8 + 0
f'(x) = 2x + 8 .
The answer is f'(x) = 2x + 8 .
2) Solve the derivative for the function f(y) = y^2 + 10y + 3
Solution : The given function is f(y) = y^2 + 10y + 3
Differentiate the above equation with respect to 'y' . It is represented as f'(y) .
f'(y) = `(d(y^2))/dy` + `(d(10y))/dy` + `(d(3))/dy`
f'(y) = 2y + 10 + 0
f'(y) = 2y + 10
The answer is f'(y) = 2y + 10
Solving third Order Derivative Functions
1) Find the derivative of the function f(x) = x3 + 3x^2 + 18x + 20
Solution : The given function f(x) = x3 + 3x^2 + 18x + 20
Differentiate the above function with respect to 'x' .
f'(x) = 3 x^2 + 3 ( 2 ) x + 18 + 0
f'(x) = 3x^2 + 6x + 18 .
The answer is f'(x) = 3x^2 + 6x + 18 .
2) Find the derivative for f(x) = 6x3 + 5x^2 + 3x + 1
Solution : The given function is f(x) = 6x3 + 5x^2 + 3x + 1
Differentiate the above f(x) with respect to 'x' .
f'(x) = 6 (3)x^2 + 5 (2)x + 3 + 0
f'(x) = 18x^2 + 10x + 3
The answer is f'(x) = 18x^2 + 10x + 3
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Solving 4th Order Derivative Function
1) Solve the derivative for the function f(y) = y^4 + 3y^3 + 5y^2 + 4y + 9
Solution : The given function f(y) = y^4 + 3y^3 + 5y^2 + 4y + 9
DIfferentiate the above equation with respect to 'y' .
f'(y) = 4y^3 + 3(3)y^2 + 5(2)y + 4 + 0
f'(y) = 4y^3 + 9y^2 + 10y + 4
The answer is f(y) = y^4 + 3y^3 + 5y^2 + 4y + 9
2) Solve the derivative for the function f(y) = 6y^4 + y^3 + y^2 + 10 y + 3
Solution : The given function is f(y) = 6y^4 + y^3 + y^2 + 10 y + 3
DIfferentiate the above equation with respect to 'y' .
f'(y) = 6(4)y^3 + 3y^2 + 2y + 10 + 0
f'(y) = 24y^3 + 3y^2 + 2y + 10
The answer is f'(y) = 24y^3 + 3y^2 + 2y + 10
Algebra is widely used in day to day activities watch out for my forthcoming posts on Derivative Calculator and Derivative of Natural log. I am sure they will be helpful.
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