Median Definition :If the generally number of values within the case is even, next the median is the mean of the two center numbers. The median is a supportive number within cases wherever the distribution contain extremely large huge values which would or else twist the data. Represent the center value of a given set of values is called median.
To locate of values set within lower value toward higher value (rising order). If the collections of data contain an odd number of ways; the median is the middle value of the place behind arrangement the listing into rising order.
Median test learning
Method for median computation
`M=(n+1)/2`
Wherever,
M- Median,
n – Entirety number of set
But here is an odd number of values, then the median is the center value of the set.
If an even number to find median first
For example the given set{2,6,8,10}
Total number of value (n) =4
Median`M=(n+1)/2`
`M=(4+1)/2`
`M=(5)/2`
M=2.5
Consequently median must appear among second and third value.
Second value=6
Third value =8
Mean of second and third value is the Median of this set
Median`M=(14)/2`
`M=(7)/2`
M=3.5
Examples for median test learning
Example 1 for median test learning
Compute the median of this set {20, 10, 12, 40, 60,50,30}.
Solution:
First values can be arranged in order
Therefore the given set={10, 12, 20, 30, 40, 50, 60}
Here, total number of value (n) =7.
Median`M=(n+1)/2`
`M=(7+1)/2`
`M=(8)/2`
M=4
Therefore the fourth value is median that is 30.
Example 2 for median test learning
Compute the median of this set {10, 12, 13, 17, 18, and 20}
Solution:
Total number of value (n) =6
Median`M=(n+1)/2`
`M=(6+1)/2`
`M=(7)/2`
M=3.5
Consequently median must appear among Third and Fourth value.
Third value=13
Fourth value =17
Mean of third and fourth value is the Median of this set
Median`M=(13+10)/2`
`M=(30)/2`
M=15
Example 3 for median test learning
Compute the median of this set {26, 32, 36, and 55}
Solution:
Total number of value (n) =4
Median`M=(n+1)/2`
`M=(4+1)/2`
`M=(5)/2`
M=2.5
Consequently median must appear among second and third value.
Second value=32
Third value =36
Mean of second and third value is the Median of this set
Median`M=(32+36)/2`
`M=(68)/2`
M=34
To locate of values set within lower value toward higher value (rising order). If the collections of data contain an odd number of ways; the median is the middle value of the place behind arrangement the listing into rising order.
Median test learning
Method for median computation
`M=(n+1)/2`
Wherever,
M- Median,
n – Entirety number of set
But here is an odd number of values, then the median is the center value of the set.
If an even number to find median first
For example the given set{2,6,8,10}
Total number of value (n) =4
Median`M=(n+1)/2`
`M=(4+1)/2`
`M=(5)/2`
M=2.5
Consequently median must appear among second and third value.
Second value=6
Third value =8
Mean of second and third value is the Median of this set
Median`M=(14)/2`
`M=(7)/2`
M=3.5
Examples for median test learning
Example 1 for median test learning
Compute the median of this set {20, 10, 12, 40, 60,50,30}.
Solution:
First values can be arranged in order
Therefore the given set={10, 12, 20, 30, 40, 50, 60}
Here, total number of value (n) =7.
Median`M=(n+1)/2`
`M=(7+1)/2`
`M=(8)/2`
M=4
Therefore the fourth value is median that is 30.
Example 2 for median test learning
Compute the median of this set {10, 12, 13, 17, 18, and 20}
Solution:
Total number of value (n) =6
Median`M=(n+1)/2`
`M=(6+1)/2`
`M=(7)/2`
M=3.5
Consequently median must appear among Third and Fourth value.
Third value=13
Fourth value =17
Mean of third and fourth value is the Median of this set
Median`M=(13+10)/2`
`M=(30)/2`
M=15
Example 3 for median test learning
Compute the median of this set {26, 32, 36, and 55}
Solution:
Total number of value (n) =4
Median`M=(n+1)/2`
`M=(4+1)/2`
`M=(5)/2`
M=2.5
Consequently median must appear among second and third value.
Second value=32
Third value =36
Mean of second and third value is the Median of this set
Median`M=(32+36)/2`
`M=(68)/2`
M=34
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